WEBVTT
Kind: captions
Language: en
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Moving on to step number five
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to calculate the dosing interval
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Dosing interval is equal to
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the natural log of peak concentration over
through concentration
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divided by K the first-order elimination rate constant
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plus cap T which is the infusion time
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and a Tau, in this case
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because we know the therapeutic window is 28 to 17,
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therefore, the tau turn out to be 10.2 hours
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and then, of course, we rounded up to 12 hours.
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So that is the desirable dosing interval in
order to constrain the concentration
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between the peak of 28 and the trough of 17.
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So based on the calculated dosing interval,
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we are going to recommend and maintenance dose
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and that maintenance dose D is equal
to the peak concentration times K times V
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times cap T times 1 minus e to the minus K tau
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divided by 1 minus e to the minus K cap T.
00:01:35.940 --> 00:01:40.680
So this is if we know the peak concentration
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that we wish to achieve at the dosing interval of tau
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and we should be able to calculate
and maintenance dose
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in order to maintain the concentration between the therapeutic window.
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Again here C peak is 28 milligram per liter.
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K is 0.0542 V is 66.4.
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The infusion time is one hour and the Tau is 12 hour.
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And the result turns out to be 912.9 mg
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and of course we rounded up to 1000 milligram.
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So the recommended maintenance dose would
be 1000 milligram per hour infusion rate.